For years I have felt like I didn't fully understand the relationship of torque and horsepower.
I mean you look up the technical description and it seems so simple.
http://en.wikipedia.org/wiki/Horsepower#Relationship_with_torque
It's also how much work can actually be done by a motor.
So where I had been confused for so long is listening to all the arguments you hear all the time.
Low end torque is better then high end hp, Hp is good on the straights but coming out of the corner you want good low end torque, The blacktop makes good high end Hp but the 2 GR makes better low end torque, ect.
I thought there must be something I am missing. People make it sound like this complicated relationship, I must not understand how it applies or something.
Finally I realized it really is that simple.
Comparing torqe to hp is like comparing apples to lemonade. Sure they might be related but you are just overcomplicating a very simple situation.
Ok so torque is easy, twisting force is all it boils down to. We americans tend to use inch pounds and foot pounds. If you don't get it read this
http://en.wikipedia.org/wiki/Torque#Relationship_between_torque_and_power
Horsepower is how much work that torque can accomplish over time.
So since for ICEs we need to worry about torque curves and such let's simplify this to two single speed electric motors.
Given optimal gearing which would acelerate your car faster, a motor that makes 400 ft/lbs of torqe at 1000 rpm or a motor that makes 75 ft/lbs of torque at 14000 RPM?
Even though the latter motor makes substantially less torque it makes considerably more hp. This means it is able to do much more work faster than the other motor.
Heres the other thing to think about.
I say given the right gearing because one will need a much greater reduction.
What does a gear reduction do? It increases torque.
So at the wheels the 14000 RPM motor will be able to deliver more torque than the 1000 rpm motor.
Remember when you dyno your car HP is measured the same (Minus drivetrain loss) at the motor as at the wheels. Torque however is much different at the motor than it is at the wheels.
Let's say you have a .5:1 gear reduction. The hp will be the same at both points, the motor would be able to move half as much twice as fast as the output after the gear reduction.
Hp is the same, torque is doubled by the gearbox.
So lets say we have a motor that makes 100 ft/lbs of torqe at 5252 rpm and we have a motor that makes 5252 ft/lbs torque at 100 rpm we have two 100 hp motors.
If we gear them so both output shafts are spinning the same rpm you will get the same amount of hp and torque out of both motors. Again of course plus or minus drivetrain loss.
So what's better apples or lemonade?
Here's a cool converter I found to find hp from torque and RPM.
http://www.ajdesigner.com/phphorsepower/horsepower_equation_rotating_horsepower.php
I mean you look up the technical description and it seems so simple.
http://en.wikipedia.org/wiki/Horsepower#Relationship_with_torque
It seems so simple. Horsepower is basically just a matter of torque and RPM.
It's also how much work can actually be done by a motor.
So where I had been confused for so long is listening to all the arguments you hear all the time.
Low end torque is better then high end hp, Hp is good on the straights but coming out of the corner you want good low end torque, The blacktop makes good high end Hp but the 2 GR makes better low end torque, ect.
I thought there must be something I am missing. People make it sound like this complicated relationship, I must not understand how it applies or something.
Finally I realized it really is that simple.
Comparing torqe to hp is like comparing apples to lemonade. Sure they might be related but you are just overcomplicating a very simple situation.
Ok so torque is easy, twisting force is all it boils down to. We americans tend to use inch pounds and foot pounds. If you don't get it read this
http://en.wikipedia.org/wiki/Torque#Relationship_between_torque_and_power
Horsepower is how much work that torque can accomplish over time.
So since for ICEs we need to worry about torque curves and such let's simplify this to two single speed electric motors.
Given optimal gearing which would acelerate your car faster, a motor that makes 400 ft/lbs of torqe at 1000 rpm or a motor that makes 75 ft/lbs of torque at 14000 RPM?
Even though the latter motor makes substantially less torque it makes considerably more hp. This means it is able to do much more work faster than the other motor.
Heres the other thing to think about.
I say given the right gearing because one will need a much greater reduction.
What does a gear reduction do? It increases torque.
So at the wheels the 14000 RPM motor will be able to deliver more torque than the 1000 rpm motor.
Remember when you dyno your car HP is measured the same (Minus drivetrain loss) at the motor as at the wheels. Torque however is much different at the motor than it is at the wheels.
Let's say you have a .5:1 gear reduction. The hp will be the same at both points, the motor would be able to move half as much twice as fast as the output after the gear reduction.
Hp is the same, torque is doubled by the gearbox.
So lets say we have a motor that makes 100 ft/lbs of torqe at 5252 rpm and we have a motor that makes 5252 ft/lbs torque at 100 rpm we have two 100 hp motors.
If we gear them so both output shafts are spinning the same rpm you will get the same amount of hp and torque out of both motors. Again of course plus or minus drivetrain loss.
So what's better apples or lemonade?
Here's a cool converter I found to find hp from torque and RPM.
http://www.ajdesigner.com/phphorsepower/horsepower_equation_rotating_horsepower.php