That makes good sense, you could write the roll center height (at zero roll for symmetric suspension, or the Force Application Point for an asymmetric case) as
H = (T/2)*tan(theta)
where T is the track width and theta is the angle formed by a line through the contact patch and the instantaneous center.
On our strut suspensions at least, a low but above-ground roll center implies instant centers relatively far away and with height higher than the roll center. So when you put the smaller diameter tires on that lower the car 0.5", the virtual swing arm angle (relative to wheel center) doesn't change, but the instant center height goes down by 0.5". But 0.5" is a relatively small portion of the total instant center height, and the roll center will fall in roughly the same proportion as the instant center. Meaning, not much. In your case based on the numbers you show, the instant center must have been roughly 20" off the ground, so you dropped it by 0.5", only a 2.5% reduction. The limit case seems weird to think of but nonetheless true: if the roll center is exactly at the road surface, it won't move when you change tire diameter (because the virtual swing arm is infinitely long so theta is always zero).
Its a nice illustration of something I've also been appreciating more myself lately as I work through the suspension geometry concepts - the suspension has to be tuned for a particular wheel/tire combination. Almost any change (with the possible exception of a small swaybar stiffness adjustment) has a cascade of side effects that are sometimes surprising.
I think there is a limit case where the roll center would drop by the same amount as the tire radius - if the instant center was at the same point as the roll center. Of course that would be a really wacky strut suspension that would never really exist, I mention it just to point out that my reasoning applies mostly to the case of our typical geometries and might not be universally applicable.
H = (T/2)*tan(theta)
where T is the track width and theta is the angle formed by a line through the contact patch and the instantaneous center.
On our strut suspensions at least, a low but above-ground roll center implies instant centers relatively far away and with height higher than the roll center. So when you put the smaller diameter tires on that lower the car 0.5", the virtual swing arm angle (relative to wheel center) doesn't change, but the instant center height goes down by 0.5". But 0.5" is a relatively small portion of the total instant center height, and the roll center will fall in roughly the same proportion as the instant center. Meaning, not much. In your case based on the numbers you show, the instant center must have been roughly 20" off the ground, so you dropped it by 0.5", only a 2.5% reduction. The limit case seems weird to think of but nonetheless true: if the roll center is exactly at the road surface, it won't move when you change tire diameter (because the virtual swing arm is infinitely long so theta is always zero).
Its a nice illustration of something I've also been appreciating more myself lately as I work through the suspension geometry concepts - the suspension has to be tuned for a particular wheel/tire combination. Almost any change (with the possible exception of a small swaybar stiffness adjustment) has a cascade of side effects that are sometimes surprising.
I think there is a limit case where the roll center would drop by the same amount as the tire radius - if the instant center was at the same point as the roll center. Of course that would be a really wacky strut suspension that would never really exist, I mention it just to point out that my reasoning applies mostly to the case of our typical geometries and might not be universally applicable.